Two circles ${S_1} = {x^2} + {y^2} + 2{g_1}x + 2{f_1}y + {c_1} = 0$ and ${S_2} = {x^2} + {y^2} + 2{g_2}x + 2{f_2}y + {c_2} = 0$ cut each other orthogonally, then
$2{g_1}{g_2} + 2{f_1}{f_2} = {c_1} + {c_2}$
$2{g_1}{g_2} - 2{f_1}{f_2} = {c_1} + {c_2}$
$2{g_1}{g_2} + 2{f_1}{f_2} = {c_1} - {c_2}$
$2{g_1}{g_2} - 2{f_1}{f_2} = {c_1} - {c_2}$
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Let the equation $x^{2}+y^{2}+p x+(1-p) y+5=0$ represent circles of varying radius $\mathrm{r} \in(0,5]$. Then the number of elements in the set $S=\left\{q: q=p^{2}\right.$ and $\mathrm{q}$ is an integer $\}$ is ..... .