Total number of molecules/species from the fo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Paramagnetic species contain at least one unpaired electron. Let us analyze each species: $1. O_2$: Has $2$ unpaired electrons in $\pi^* 2p$ orbit

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) Paramagnetic species contain at least one unpaired electron. Let us analyze each species: $1. O_2$: Has $2$ unpaired electrons in $\pi^* 2p$ orbitals. (Paramagnetic) $2. O_2^{+}$: Has $1$ unpaired electron. (Paramagnetic) $3. O_2^{-}$: Has $1$ unpaired electron. (Paramagnetic) $4. NO$: Has $15$ electrons (odd electron species). (Paramagnetic) $5. NO_2$: Has $23$ electrons (odd electron species). (Paramagnetic) $6. CO$: Has $14$ electrons,all paired. (Diamagnetic) $7. K_2[NiCl_4]$: $Ni^{2+}$ is $3d^8$. $Cl^-$ is a weak field ligand,so it forms a tetrahedral complex with $2$ unpaired electrons. (Paramagnetic) $8. [Co(NH_3)_6]Cl_3$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,so it forms an octahedral complex with all electrons paired. (Diamagnetic) $9. K_2[Ni(CN)_4]$: $Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,so it forms a square planar complex with all electrons paired. (Diamagnetic) The paramagnetic species are $O_2, O_2^{+}, O_2^{-}, NO, NO_2, K_2[NiCl_4]$. The total count is $6$.

List-$I$	List-$II$
$(A). [Ag(CN)_2]^-$	$1. \text{Square planar, } 1.73 \, B.M.$
$(B). [Cu(CN)_4]^{3-}$	$2. \text{Linear, } 0 \, B.M.$
$(C). [Cu(CN)_6]^{4-}$	$3. \text{Octahedral, } 0 \, B.M.$
$(D). [Cu(NH_3)_4]^{2+}$	$4. \text{Tetrahedral, } 0 \, B.M.$
$(E). [Fe(CN)_6]^{4-}$	$5. \text{Octahedral, } 1.73 \, B.M.$

Total number of molecules/species from the following which will be paramagnetic is $........$
$O_2, O_2^{+}, O_2^{-}, NO, NO_2, CO, K_2[NiCl_4], [Co(NH_3)_6]Cl_3, K_2[Ni(CN)_4]$

Similar Questions

Consider the following complexes:
$(a) \ Na_2[Fe(CN)_5NO]$
$(b) \ [Fe(H_2O)_5NO]SO_4$
$(c) \ K_4[Fe(CN)_6]$
Which of the following statements is wrong?

Give the oxidation state,$d$-orbital occupation,and coordination number of the central metal ion in the following complexes:
$(i)$ $K_{3}[Co(C_{2}O_{4})_{3}]$
$(ii)$ $cis-[Cr(en)_{2}Cl_{2}]Cl$
$(iii)$ $(NH_{4})_{2}[CoF_{4}]$
$(iv)$ $[Mn(H_{2}O)_{6}]SO_{4}$

$0.001 \ mol$ of $Co(NH_3)_5(NO_3)(SO_4)$ was passed through a cation exchanger. The acid coming out of it required $20 \ mL$ of $0.1 \ M$ $NaOH$ for neutralization. Hence,the complex is:

$A$ coordination compound has the formula $MCl_3 \cdot 4H_2O$. The coordination number of the metal is $6$,and it contains no water of hydration. How many $ml$ of $0.1 \, M \, AgNO_3$ are required to precipitate the chloride ions from $200 \, ml$ of a $0.01 \, M$ solution of this compound?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Total number of molecules/species from the following which will be paramagnetic is $........$ $O_2, O_2^{+}, O_2^{-}, NO, NO_2, CO, K_2[NiCl_4], [Co(NH_3)_6]Cl_3, K_2[Ni(CN)_4]$