Match List-$I$ with List-$II$ and select the correct option:
List-$I$List-$II$
$(A). [Ag(CN)_2]^-$$1. \text{Square planar, } 1.73 \, B.M.$
$(B). [Cu(CN)_4]^{3-}$$2. \text{Linear, } 0 \, B.M.$
$(C). [Cu(CN)_6]^{4-}$$3. \text{Octahedral, } 0 \, B.M.$
$(D). [Cu(NH_3)_4]^{2+}$$4. \text{Tetrahedral, } 0 \, B.M.$
$(E). [Fe(CN)_6]^{4-}$$5. \text{Octahedral, } 1.73 \, B.M.$

  • A
    $A-2, B-4, C-5, D-1, E-3$
  • B
    $A-5, B-4, C-1, D-3, E-2$
  • C
    $A-1, B-3, C-4, D-2, E-5$
  • D
    $A-4, B-5, C-2, D-1, E-3$

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Similar Questions

Identify the correct set from the following table:

Given below are two statements:
Statement-$I$: Hybridisation,shape,and spin-only magnetic moment of $K_{3}[Co(CO_{3})_{3}]$ are $sp^{3}d^{2}$,octahedral,and $4.9 \ BM$ respectively.
Statement-$II$: Geometry,hybridisation,and spin-only magnetic moment values $(BM)$ of the ions $[Ni(CN)_{4}]^{2-}$,$[MnBr_{4}]^{2-}$,and $[CoF_{6}]^{3-}$ respectively are square planar,tetrahedral,octahedral; $dsp^{2}$,$sp^{3}$,$sp^{3}d^{2}$ and $0, 5.9, 4.9$.

When a metal rod $M$ is dipped into an aqueous colourless concentrated solution of compound $N$,the solution turns light blue. Addition of aqueous $NaCl$ to the blue solution gives a white precipitate $O$. Addition of aqueous $NH_3$ dissolves $O$ and gives an intense blue solution.
$1.$ The metal rod $M$ is
$(A)$ $Fe$ $(B)$ $Cu$ $(C)$ $Ni$ $(D)$ $Co$
$2.$ The compound $N$ is
$(A)$ $AgNO_3$ $(B)$ $Zn(NO_3)_2$
$(C)$ $Al(NO_3)_3$ $(D)$ $Pb(NO_3)_2$
$3.$ The final solution contains
$(A)$ $[Pb(NH_3)_4]^{2+}$ and $[CoCl_4]^{2-}$
$(B)$ $[Al(NH_3)_4]^{3+}$ and $[Cu(NH_3)_4]^{2+}$
$(C)$ $[Ag(NH_3)_2]^{+}$ and $[Cu(NH_3)_4]^{2+}$
$(D)$ $[Ag(NH_3)_2]^{+}$ and $[Ni(NH_3)_6]^{2+}$
Give the answer for questions $1$,$2$ and $3$.

$0.02 \, \text{mole}$ of $[Co(NH_3)_5Br]Cl_2$ and $0.02 \, \text{mole}$ of $[Co(NH_3)_5Cl]SO_4$ are present in $200 \, \text{cc}$ of a solution $X$. The number of moles of the precipitates $Y$ and $Z$ that are formed when the solution $X$ is treated with excess silver nitrate and excess barium chloride are respectively:

The coordination number of $Ni^{2+}$ is $4$.
$NiCl_2 + KCN$ (excess) $\rightarrow A$ (cyano complex)
$NiCl_2 + \text{Conc. } HCl$ (excess) $\rightarrow B$ (chloro complex)
$1.$ The $IUPAC$ names of $A$ and $B$ are:
$(A)$ Potassium tetracyanonickelate $(II)$,potassium tetrachloronickelate $(II)$
$(B)$ Tetracyanopotassiumnickelate $(II)$,tetrachloropotassiumnickelate $(II)$
$(C)$ Tetracyanonickel $(II)$,tetrachloronickel $(II)$
$(D)$ Potassium tetracyanonickel $(II)$,potassium tetrachloronickel $(II)$
$2.$ Predict the magnetic nature of $A$ and $B$:
$(A)$ Both are diamagnetic.
$(B)$ $A$ is diamagnetic and $B$ is paramagnetic with one unpaired electron.
$(C)$ $A$ is diamagnetic and $B$ is paramagnetic with two unpaired electrons.
$(D)$ Both are paramagnetic.
$3.$ The hybridization of $A$ and $B$ are:
$(A)$ $dsp^2, sp^3$
$(B)$ $sp^3, sp^3$
$(C)$ $dsp^2, dsp^2$
$(D)$ $sp^3 d^2, d^2 sp^3$
Give the answers for questions $1, 2$ and $3$.

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