To estimate $g$ from $g=4 \pi^2 \frac{L}{T^2}$,the error in the measurement of $L$ is $\pm 2 \%$ and the error in the measurement of $T$ is $\pm 3 \%$. The error in the estimated $g$ will be

$A$ physical parameter $a$ can be determined by measuring the parameters $b, c, d$ and $e$ using the relation $a = \frac{b^\alpha c^\beta}{d^\gamma e^\delta}$. If the maximum percentage errors in the measurement of $b, c, d$ and $e$ are $b_1\%, c_1\%, d_1\%$ and $e_1\%$ respectively,then the maximum percentage error in the value of $a$ determined by the experiment is:

If $Q = \frac{X^n}{Y^m}$ and $\Delta X$ is the absolute error in the measurement of $X$,and $\Delta Y$ is the absolute error in the measurement of $Y$,then the absolute error $\Delta Q$ in $Q$ is:

In an experiment of a simple pendulum,the time period measured was $50 \, s$ for $25$ vibrations when the length of the simple pendulum was taken as $100 \, cm$. If the least count of the stopwatch is $0.1 \, s$ and that of the meter scale is $0.1 \, cm$,then the maximum possible error in the value of $g$ is .......... $\%$

Why is the error in a measurement expressed with both positive and negative signs?

If the error in the measurement of the radius of a sphere is $2\%$,then the error in the determination of the volume of the sphere will be ........ $\%$