Three masses are placed on the x-axis : 300, | vedclass

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Question

The distance of the center of mass of the system of three masses from the origin $O$ is

${X_{CM}} = \frac{{{m_1}{x_1} + {m_2}{x_2} + {m_3}{x_3}}}{{

Vedclass · Accepted Answer

$40$

Vedclass · Answer

The distance of the center of mass of the system of three masses from the origin $O$ is

${X_{CM}} = \frac{{{m_1}{x_1} + {m_2}{x_2} + {m_3}{x_3}}}{{{m_1} + {m_2} + {m_3}}}$
$= \frac{{300 	imes 0 + 500 	imes 40 + 400 	imes 70}}{{300 + 500 + 400}}$
$= \frac{{500 	imes 40 + 400 	imes 70 400\left[ {50 + 70} ight]}}{{1200 1200}}$

$= \frac{{50 + 70}}{3} \cdot  = \frac{{120}}{3} \cdot  = 40\,cm$

Three masses are placed on the $x-$axis $: 300\, g$ at origin, $500 \,g$ at $x = 40\, cm$ and $400\, g$ at $x = 70\, cm.$ The distance of the centre of mass from the origin is ....... $cm$

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