Seven identical homogeneous bricks, each of length $L$ , are arranged as shown in figure. Each brick is displaced with respect to the one in contacts by $\frac{L}{{10}}$ . Calculate the $x$-co-ordinate of the centre of mass of this system relative to the origin $O$ as shown
$\frac{{2L}}{5}$
$\frac{{7L}}{10}$
$\frac{{7L}}{21}$
$\frac{{22L}}{35}$
Locate the centre of mass of arrangement shown in figure. The three rods are identical in mass and length
Obtain the position of centre of mass of a thin rod of uniform density.
A wheel in uniform motion about an axis passing through its centre and perpendicular to its plane is considered to be in mechanical (translational plus rotational) equilibrium because no net external force or torque is required to sustain its motion. However, the particles that constitute the wheel do experience a centripetal the acceleration directed towards the centre. How do you reconcile this fact with the wheel being in equilibrium?
How would you set a half wheel into uniform motion about an axis passing through the centre of mass of the wheel and perpendicular to its plane? Will you require external forces to sustain the motion ?
Two point masses $m$ and $M$ are separated by a distance $L$. The distance of the centre of mass of the system from m is