Three circles lie on a plane such that each of them externally touches the other two. Two of them have radius $3$,and the third has radius $1$. If $A, B$,and $C$ are the points of tangency of the circles,then the area of the triangle $ABC$ is

  • A
    $\frac{9\sqrt{7}}{4}$
  • B
    $\frac{9\sqrt{7}}{8}$
  • C
    $\frac{9\sqrt{3}}{16}$
  • D
    None of these

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