There long straight wires $A$, $B$ and $C$ are carrying current as shown figure. Then the resultant force on $B$ is directed .....

An infinitely long straight conductor $AB$ is fixed and a current is passed through it. Another movable straight wire $CD$ of finite length and carrying current is held perpendicular to it and released. Neglect weight of the wire

A triangular shaped wire carrying $10 A$ current is placed in a uniform magnetic field of $0.5\,T$, as shown in figure. The magnetic force on segment $CD$ is $....N$ $($ Given $BC = CD = BD =5\,cm )$.

A square loop of area $25\,cm ^2$ has a resistance of $10\,\Omega$. The loop is placed in uniform magnetic field of magnitude $40.0 T$. The plane of loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in $1.0 sec$, will be $..........\times 10^{-3}$

The horizontal component of earth's magnetic field at a place is $3.5 \times 10^{-5} \mathrm{~T}$. A very long straight conductor carrying current of $\sqrt{2} A$ in the direction from South east to North West is placed. The force per unit length experienced by the conductor is$..............$ $\times 10^{-6} \mathrm{~N} / \mathrm{m}$.

Assertion $(A):$ A wire bent into an irregular shape with the points $P$ and $Q$ fixed. If a current $I$ passed through the wire, then the area enclosed by the irregular portion of the wire increases.

Reason $(R):$ Opposite currents carrying wires repel each other.