Two long and parallel straight wires A and B | vedclass

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Question

Current flowing in wire $A, I_{A}=8.0 \mathrm{A}$

Current flowing in wire $\mathrm{B}, \mathrm{I}_{\mathrm{B}}=5.0 \mathrm{A}$

Distance between

Vedclass · Accepted Answer

$2	imes10^{-5}$ Attractive

Vedclass · Answer

Current flowing in wire $A, I_{A}=8.0 \mathrm{A}$

Current flowing in wire $\mathrm{B}, \mathrm{I}_{\mathrm{B}}=5.0 \mathrm{A}$

Distance between the two wires, $r=4.0 \mathrm{cm}=0.04 \mathrm{m}$

Length of a section of wire $A, I=10 \mathrm{cm}=0.1 \mathrm{m}$

Force exerted on length I due to the magnetic field is given as:

$B=\frac{\mu_{0} 2 I_{\mathrm{A}} I_{\mathrm{B}} l}{4 \pi r}$

Where,

$\mu_{0}=$ Permeability of free space $=4 \pi 	imes 10^{-7} \mathrm{T} \mathrm{m} \mathrm{A}^{-1}$

$B=\frac{4 \pi 	imes 10^{-7} 	imes 2 	imes 8 	imes 5 	imes 0.1}{4 \pi 	imes 0.04}$

$=2 	imes 10^{-5} \mathrm{N}$

The magnitude of force is $2 	imes 10^{-5} \mathrm{N}$. This is an attractive force normal to A towards

B because the direction of the currents in the wires is the same.

Two long and parallel straight wires $A$ and $B$ carrying currents of $8.0\, A$ and $5.0\, A$ in the same direction are separated by a distance of $4.0\, cm$. Estimate the force on a $10\, cm$ section of wire $A$

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