There are chits numbered 1 to 20 in a box. On | vedclass

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(C) The total number of chits in the box is $n(S) = 20$.The chits are numbered from $1$ to $20$.The odd numbers between $1$ and $20$ are $1, 3, 5, 7,

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$1/2$

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(C) The total number of chits in the box is $n(S) = 20$.The chits are numbered from $1$ to $20$.The odd numbers between $1$ and $20$ are $1, 3, 5, 7, 9, 11, 13, 15, 17, 19$.The number of odd-numbered chits is $n(E) = 10$.The probability $P(E)$ of drawing an odd-numbered chit is given by the formula $P(E) = \frac{n(E)}{n(S)}$.Substituting the values,we get $P(E) = \frac{10}{20} = \frac{1}{2}$.

There are chits numbered $1$ to $20$ in a box. One chit is drawn at random. Find the probability that the number on the chit is an odd number.

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