Find the probability that a leap year has 53 | vedclass

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(C) leap year has $366$ days,which is equivalent to $52$ complete weeks and $2$ extra days.Since $52$ weeks contain $52$ Thursdays,the occurrence of a

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$\frac{2}{7}$

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(C) leap year has $366$ days,which is equivalent to $52$ complete weeks and $2$ extra days.Since $52$ weeks contain $52$ Thursdays,the occurrence of a $53$rd Thursday depends on the remaining $2$ days.The possible pairs for these $2$ days are:(Sunday,Monday),(Monday,Tuesday),(Tuesday,Wednesday),(Wednesday,Thursday),(Thursday,Friday),(Friday,Saturday),(Saturday,Sunday).There are $7$ total possible outcomes.The outcomes that include a Thursday are (Wednesday,Thursday) and (Thursday,Friday).Thus,there are $2$ favorable outcomes.The probability is calculated as $\frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{2}{7}$.

Find the probability that a leap year has $53$ Thursdays.

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