There are $3$ bags $A, B$ & $C$. Bag $A$ contains $1$ Red & $2$ Green balls, bag $B$ contains $2$ Red & $1$ Green balls and bag $C$ contains only one green ball. One ball is drawn from bag $A$ & put into bag $B$ then one ball is drawn from $B$ & put into bag $C$ & finally one ball is drawn from bag $C$ & put into bag $A$. When this operation is completed, probability that bag $A$ contains $2$ Red & $1$ Green balls, is -

  • A

    $\frac{1}{4}$

  • B

    $\frac{1}{2}$

  • C

    $\frac{1}{3}$

  • D

    $\frac{1}{6}$

Similar Questions

A bag contains $3$ red, $4$ white and $5$ blue balls. All balls are different. Two balls are drawn at random. The probability that they are of different colour is

A bag contains $5$ black balls, $4$ white balls and $3$ red balls. If a ball is selected randomwise, the probability that it is a black or red ball is

A fair dice is thrown up to $20$ times. The probability that on the $10^{th}$ throw, the fourth six apears is :-

There are $n$ letters and $n$ addressed envelops. The probability that each letter takes place in right envelop is

If out of $20$ consecutive whole numbers two are chosen at random, then the probability that their sum is odd, is