A fair dice is thrown up to $20$ times. The probability that on the $10^{th}$ throw, the fourth six apears is :-

  • A

    $\frac{{84 \times {5^6}}}{{{6^{10}}}}$

  • B

    $\frac{{112 \times {5^6}}}{{{6^{10}}}}$

  • C

    $\frac{{84 \times {5^6}}}{{{6^{20}}}}$

  • D

    None

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