The zeros of a polynomial p(x) = x^{2} - 2x - | vedclass

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(C) To find the zeros of the polynomial $p(x) = x^{2} - 2x - 15$,we set $p(x) = 0$.$x^{2} - 2x - 15 = 0$We need to factorize the quadratic equation by

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$5$ and $-3$

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(C) To find the zeros of the polynomial $p(x) = x^{2} - 2x - 15$,we set $p(x) = 0$.$x^{2} - 2x - 15 = 0$We need to factorize the quadratic equation by splitting the middle term. We look for two numbers whose product is $-15$ and whose sum is $-2$.These numbers are $-5$ and $3$.$x^{2} - 5x + 3x - 15 = 0$$x(x - 5) + 3(x - 5) = 0$$(x - 5)(x + 3) = 0$Setting each factor to zero:$x - 5 = 0 \implies x = 5$$x + 3 = 0 \implies x = -3$Therefore,the zeros of the polynomial are $5$ and $-3$.

The zeros of a polynomial $p(x) = x^{2} - 2x - 15$ are........

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