(B) Let the work function of metal $A$ be $\phi_A = \phi_0$ and metal $B$ be $\phi_B = 2\phi_0$.According to Einstein's photoelectric equation,the max

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(B) Let the work function of metal $A$ be $\phi_A = \phi_0$ and metal $B$ be $\phi_B = 2\phi_0$.According to Einstein's photoelectric equation,the maximum kinetic energy $E_K$ is given by $E_K = h\nu - \phi$.For metal $A$: $E_{K_A} = hf - \phi_0$.For metal $B$: $E_{K_B} = h(2f) - 2\phi_0 = 2(hf - \phi_0)$.Taking the ratio of the maximum kinetic energies:$\frac{E_{K_A}}{E_{K_B}} = \frac{hf - \phi_0}{2(hf - \phi_0)} = \frac{1}{2}$.Thus,the ratio is $1 : 2$.

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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The work functions of metals $A$ and $B$ are in the ratio $1 : 2$. If light of frequencies $f$ and $2f$ are incident on the surfaces of $A$ and $B$ respectively,the ratio of the maximum kinetic energy of photoelectrons emitted will be ($f$ and $2f$ are both frequencies greater than the threshold frequency of metals $A$ and $B$).

A
$1 : 1$
B
$1 : 2$
C
$1 : 3$
D
$1 : 4$

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Class 12 Questions

Class 12

Physics Questions

Chapter

Dual Nature of Radiation and matter

Subtopic

Einstein's Photoelectric Equation and Energy Quantum of Radiation

Photons with energy $5\, eV$ are incident on a cathode $C$ in a photoelectric cell. The maximum energy of emitted photoelectrons is $2\, eV.$ When photons of energy $6\, eV$ are incident on $C,$ no photoelectrons will reach the anode $A,$ if the stopping potential of $A$ relative to $C$ is ............ $V$.

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The figure showing the correct relationship between the stopping potential $V_0$ and the frequency $\nu$ of light for potassium and tungsten is

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The work functions for sodium and copper are $2 \ eV$ and $4 \ eV$, respectively. Which of them is suitable for a photocell using $4000 \ \mathring{A}$ light?

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The kinetic energy of the photoelectrons increases by $0.52 eV$ when the wavelength of incident light is changed from $500 \,nm$ to another wavelength. The new wavelength is approximately: (in $\,nm$)

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For photoelectric emission from a certain metal,the cutoff frequency is $\nu$. If radiation of frequency $2\nu$ impinges on the metal plate,the maximum possible velocity of the emitted electron will be ($m$ is the electron mass).

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The figure showing the correct relationship between the stopping potential $V_0$ and the frequency $\nu$ of light for potassium and tungsten is

The work functions for sodium and copper are $2 \ eV$ and $4 \ eV$, respectively. Which of them is suitable for a photocell using $4000 \ \mathring{A}$ light?

The kinetic energy of the photoelectrons increases by $0.52 eV$ when the wavelength of incident light is changed from $500 \,nm$ to another wavelength. The new wavelength is approximately: (in $\,nm$)

For photoelectric emission from a certain metal,the cutoff frequency is $\nu$. If radiation of frequency $2\nu$ impinges on the metal plate,the maximum possible velocity of the emitted electron will be ($m$ is the electron mass).

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