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Question

(C) According to Einstein's photoelectric equation,the stopping potential $V_0$ is related to the frequency $
u$ of incident light by the equation: $

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(C) According to Einstein's photoelectric equation,the stopping potential $V_0$ is related to the frequency $
u$ of incident light by the equation: $eV_0 = h
u - \phi$,where $h$ is Planck's constant,$e$ is the charge of an electron,and $\phi$ is the work function of the metal.This can be rewritten as: $V_0 = \left( \frac{h}{e} ight) 
u - \frac{\phi}{e}$.This equation represents a straight line of the form $y = mx + c$,where the slope $m = \frac{h}{e}$.Since the slope $\frac{h}{e}$ is a universal constant,the graphs of $V_0$ versus $
u$ for different metals must be parallel straight lines.The x-intercept of these lines is the threshold frequency $
u_0 = \frac{\phi}{h}$,which depends on the work function $\phi$ of the specific metal.Therefore,the correct representation is a set of parallel straight lines with different x-intercepts,as shown in option $C$.

The figure showing the correct relationship between the stopping potential $V_0$ and the frequency $\nu$ of light for potassium and tungsten is

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