The work done in placing a charge of 8 times | vedclass

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(D) The work done $(W)$ in charging a capacitor is given by the formula: $W = \frac{Q^2}{2C}$.Given:Charge $(Q)$ = $8 	imes 10^{-18} 	ext{ C}$Capaci

Vedclass · Accepted Answer

$32 	imes 10^{-32} 	ext{ J}$

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(D) The work done $(W)$ in charging a capacitor is given by the formula: $W = \frac{Q^2}{2C}$.Given:Charge $(Q)$ = $8 	imes 10^{-18} 	ext{ C}$Capacitance $(C)$ = $100 \mu	ext{F} = 100 	imes 10^{-6} 	ext{ F} = 10^{-4} 	ext{ F}$.Substituting the values into the formula:$W = \frac{(8 	imes 10^{-18})^2}{2 	imes 10^{-4}}$$W = \frac{64 	imes 10^{-36}}{2 	imes 10^{-4}}$$W = 32 	imes 10^{-32} 	ext{ J}$.

The work done in placing a charge of $8 \times 10^{-18} \text{ C}$ on a condenser of capacity $100 \mu\text{F}$ is:

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