The waves of $600 \ \mu m$ wavelength are incident normally on a slit of $1.2 \ mm$ width. The value of diffraction angle corresponding to the first minima will be (in radian) -

In a Fraunhofer diffraction due to a single slit,the diffraction pattern is formed on the focal plane of a lens of focal length $f = 1 \ m$. The width of the slit is $a = 0.3 \ mm$. If the third minimum is formed at a distance of $5 \ mm$ from the central maximum,find the wavelength of light in $\mathring{A}$.

Angular width of the central maximum of a diffraction pattern due to a single slit does not depend upon:

The first diffraction minima due to a single slit diffraction is at $\theta = 30^o$ for a light of wavelength $5000 \,\mathring{A}$. The width of the slit is

$A$ single slit of width $a$ is illuminated by violet light of wavelength $400 \ nm$ and the width of the diffraction pattern is measured as $y.$ When half of the slit width is covered and illuminated by yellow light of wavelength $600 \ nm$,the width of the diffraction pattern is

$A$ parallel beam of monochromatic light falls normally on a single narrow slit. The angular width of the central maximum in the resulting diffraction pattern