(B) The angular width of the central maximum in a single-slit diffraction pattern is given by the formula $\theta = \frac{2\lambda}{d}$,where $\lambda

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decreases with an increase in slit width

(B) The angular width of the central maximum in a single-slit diffraction pattern is given by the formula $\theta = \frac{2\lambda}{d}$,where $\lambda$ is the wavelength of the light and $d$ is the width of the slit.From this relation,it is clear that the angular width $\theta$ is inversely proportional to the slit width $d$ (i.e.,$\theta \propto \frac{1}{d}$).Therefore,as the slit width $d$ increases,the angular width of the central maximum decreases.

Class 12 Physics Wave Optics Single Slit Diffraction of Light

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$A$ parallel beam of monochromatic light falls normally on a single narrow slit. The angular width of the central maximum in the resulting diffraction pattern

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decreases with a decrease in slit width
B
decreases with an increase in slit width
C
increases with an increase in slit width
D
may increase or decrease

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Single Slit Diffraction of Light

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In a single slit diffraction pattern,if the first maxima of light of wavelength $\lambda$ coincides with the first minima of yellow light $(540 \ nm)$,then $\lambda$ is ......... $nm$.

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$A$ plane wavefront $(\lambda = 6 \times 10^{-7} \, m)$ falls on a slit $0.4 \, mm$ wide. $A$ convex lens of focal length $0.8 \, m$ placed behind the slit focuses the light on a screen. What is the linear diameter of the second maximum in $mm$?

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At the first minimum adjacent to the central maximum of a single-slit diffraction pattern,the phase difference between the Huygens' wavelet from the edge of the slit and the wavelet from the midpoint of the slit is

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The width of the $nth$ $HPZ$ (Half Period Zone) will be:

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In a single slit diffraction pattern,the wavelength of light used is $628 \text{ nm}$ and slit width is $0.2 \text{ mm}$. The angular width of the central maximum is $\alpha \times 10^{-2} \text{ degrees}$. The value of $\alpha$ is . . . . . . . (Take $\pi = 3.14$)

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$A$ parallel beam of monochromatic light falls normally on a single narrow slit. The angular width of the central maximum in the resulting diffraction pattern

Similar Questions

In a single slit diffraction pattern,if the first maxima of light of wavelength $\lambda$ coincides with the first minima of yellow light $(540 \ nm)$,then $\lambda$ is ......... $nm$.

$A$ plane wavefront $(\lambda = 6 \times 10^{-7} \, m)$ falls on a slit $0.4 \, mm$ wide. $A$ convex lens of focal length $0.8 \, m$ placed behind the slit focuses the light on a screen. What is the linear diameter of the second maximum in $mm$?

At the first minimum adjacent to the central maximum of a single-slit diffraction pattern,the phase difference between the Huygens' wavelet from the edge of the slit and the wavelet from the midpoint of the slit is

The width of the $nth$ $HPZ$ (Half Period Zone) will be:

In a single slit diffraction pattern,the wavelength of light used is $628 \text{ nm}$ and slit width is $0.2 \text{ mm}$. The angular width of the central maximum is $\alpha \times 10^{-2} \text{ degrees}$. The value of $\alpha$ is . . . . . . . (Take $\pi = 3.14$)

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