The wavelengths of given light waves in air a | vedclass

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(C) The refractive index $\mu$ of a medium is given by the ratio of the wavelength in vacuum (or air) $\lambda_a$ to the wavelength in the medium $\la

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$\sin ^{-1}\left(\frac{2}{3}\right)$

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(C) The refractive index $\mu$ of a medium is given by the ratio of the wavelength in vacuum (or air) $\lambda_a$ to the wavelength in the medium $\lambda_m$: $\mu = \frac{\lambda_a}{\lambda_m} = \frac{6000 \ Å}{4000 \ Å} = \frac{6}{4} = \frac{3}{2}$. The relationship between the critical angle $C$ and the refractive index $\mu$ is given by: $\sin C = \frac{1}{\mu}$. Substituting the value of $\mu$: $\sin C = \frac{1}{3/2} = \frac{2}{3}$. Therefore,the critical angle is: $C = \sin ^{-1}\left(\frac{2}{3}\right)$.

The wavelengths of given light waves in air and in a medium are $6000 \ Å$ and $4000 \ Å$ respectively. The critical angle is

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