The wavelength of an electron and a neutron w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given that the de Broglie wavelengths are equal: $\lambda_{e} = \lambda_{N}$.Using the de Broglie relation $\lambda = \frac{h}{mv}$,we have $\frac

Vedclass · Accepted Answer

$1758$

Vedclass · Answer

(B) Given that the de Broglie wavelengths are equal: $\lambda_{e} = \lambda_{N}$.Using the de Broglie relation $\lambda = \frac{h}{mv}$,we have $\frac{h}{m_{e} v_{e}} = \frac{h}{m_{N} v_{N}}$.This simplifies to $m_{e} v_{e} = m_{N} v_{N}$,or $v_{e} = \frac{m_{N}}{m_{e}} v_{N}$.Given $v_{e} = x \ v_{N}$,we have $x = \frac{m_{N}}{m_{e}}$.Substituting the values: $x = \frac{1.6 	imes 10^{-27} \ kg}{9.1 	imes 10^{-31} \ kg}$.$x = \frac{1.6}{9.1} 	imes 10^{4} = 0.175824 	imes 10^{4} = 1758.24$.The nearest integer value of $x$ is $1758$.

The wavelength of an electron and a neutron will become equal when the velocity of the electron is $x$ times the velocity of the neutron. The value of $x$ is (Nearest Integer). (Mass of electron is $9.1 \times 10^{-31} \ kg$ and mass of neutron is $1.6 \times 10^{-27} \ kg$)

Similar Questions

If a moving proton,deuteron,and alpha particle have the same De Broglie wavelength,then what is the correct order of their kinetic energy?

The atomic masses of $He$ and $Ne$ are $4$ and $20 \ amu$,respectively. The value of the de Broglie wavelength of $He$ gas at $-73^{\circ} C$ is $M$ times that of the de Broglie wavelength of $Ne$ at $727^{\circ} C$. $M$ is

The de Broglie wavelength of a particle $X$ moving with a certain velocity is $1 \ \mathring{A}$. If the mass of $Y$ is $25\%$ of $X$ and its velocity is $75\%$ of $X$,then the de Broglie wavelength of $Y$ will be ........... $\mathring{A}$.

The ratio of de-Broglie wavelength of two particles $A$ and $B$ is $2: 1$. If the velocities of $A$ and $B$ are $0.05 \ ms^{-1}$ and $0.02 \ ms^{-1}$,respectively,then the ratio of their masses $m_A: m_B$ must be

Calculate the mass of a photon,if its wavelength is given as $0.35 \ nm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module