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(C) The minimum wavelength (cutoff wavelength) of $X$-rays is given by the formula: $\lambda_{\min} = \frac{hc}{eV}$,where $eV$ is the kinetic energy

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$K.E.$ of electrons striking the target is increased

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(C) The minimum wavelength (cutoff wavelength) of $X$-rays is given by the formula: $\lambda_{\min} = \frac{hc}{eV}$,where $eV$ is the kinetic energy $(K.E.)$ of the electrons striking the target.From this relation,we can see that $\lambda_{\min} \propto \frac{1}{K.E.}$.Therefore,when the kinetic energy $(K.E.)$ of the electrons striking the target is increased,the wavelength $\lambda_{\min}$ decreases.

The wavelength of $X$-rays decreases,when

Similar Questions

$STATEMENT-1$: If the accelerating potential in an $X$-ray tube is increased, the wavelengths of the characteristic $X$-rays do not change. because
$STATEMENT-2$: When an electron beam strikes the target in an $X$-ray tube, part of the kinetic energy is converted into $X$-ray energy.

If a voltage applied to an $X$-ray tube is increased to $1.5$ times, the minimum wavelength $(\lambda_{\min})$ of an $X$-ray continuous spectrum shifts by $\Delta \lambda = 26 \, pm$. The initial voltage applied to the tube is:

Characteristic $X$-rays are produced due to

$X-$rays are produced due to

The waves emitted when a metal target is bombarded with high energy electrons are

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