The voltage V_0 in the network shown is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the given circuit, there are two diodes connected in parallel: a Silicon $(Si)$ diode with a threshold voltage of $0.7 \, V$ and a green $LED$

Vedclass · Accepted Answer

$V_0=11.3 \, V$

Vedclass · Answer

(A) In the given circuit, there are two diodes connected in parallel: a Silicon $(Si)$ diode with a threshold voltage of $0.7 \, V$ and a green $LED$ with a threshold voltage of $2.2 \, V$.When a voltage is applied, the diode with the lower threshold voltage will conduct first.Since the threshold voltage of the $Si$ diode $(0.7 \, V)$ is less than that of the $LED$ $(2.2 \, V)$, the $Si$ diode will become forward-biased and conduct, while the $LED$ remains effectively off (open circuit).Therefore, the circuit behaves as if only the $Si$ diode is present in parallel with the $12 \, V$ source.The voltage $V_0$ across the $2.2 \, k\Omega$ resistor is determined by the voltage drop across the $Si$ diode.$V_0 = 12 \, V - 0.7 \, V = 11.3 \, V$.

The voltage $V_0$ in the network shown is

Similar Questions

If $p-n$ junction diode is reverse biased,then:

If $Si$ and $Ge$ diodes have barrier potentials of $0.7 \ V$ and $0.3 \ V$ respectively,as shown in the circuit,find the values of $V_0$ and $I$. If the $Ge$ diode connection is reversed,find the new values of $V_0$ and $I$ respectively.

The increase in the width of the depletion region in a $p-n$ junction diode is due to

$A$ junction diode has a resistance of $50 \, \Omega$ when forward biased and $5000 \, \Omega$ when reverse biased. The current in the arrangement shown in the figure will be

The breakdown in a reverse biased $p-n$ junction diode is more likely to occur due to

Vedclass Test Series

Exam Paper Generator

Online Exam Module