The vertices of Delta PQR are P(2, 1),Q(-2, 3 | vedclass

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(A) The vertices of $\Delta PQR$ are $P(2, 1)$,$Q(-2, 3)$,and $R(4, 5)$.Let $RL$ be the median through vertex $R$. Therefore,$L$ is the midpoint of $P

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$3x - 4y + 8 = 0$

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(A) The vertices of $\Delta PQR$ are $P(2, 1)$,$Q(-2, 3)$,and $R(4, 5)$.Let $RL$ be the median through vertex $R$. Therefore,$L$ is the midpoint of $PQ$.Using the midpoint formula,the coordinates of $L$ are $\left(\frac{2 + (-2)}{2}, \frac{1 + 3}{2}\right) = (0, 2)$.The median $RL$ passes through $R(4, 5)$ and $L(0, 2)$.The equation of a line passing through $(x_1, y_1)$ and $(x_2, y_2)$ is $y - y_1 = \frac{y_2 - y_1}{x_2 - x_1}(x - x_1)$.Substituting the points $(4, 5)$ and $(0, 2)$:$y - 5 = \frac{2 - 5}{0 - 4}(x - 4)$$y - 5 = \frac{-3}{-4}(x - 4)$$4(y - 5) = 3(x - 4)$$4y - 20 = 3x - 12$$3x - 4y + 8 = 0$.

The vertices of $\Delta PQR$ are $P(2, 1)$,$Q(-2, 3)$,and $R(4, 5)$. Find the equation of the median through the vertex $R$.

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