If the coordinates of the vertices of the triangle $ABC$ be $(-1, 6)$, $(-3, -9)$, and $(5, -8)$ respectively, then the equation of the median through $C$ is
If the coordinates of the vertices of the triangle $ABC$ be $(-1, 6)$, $(-3, -9)$, and $(5, -8)$ respectively, then the equation of the median through $C$ is
- A
$13x - 14y - 47 = 0$
- B
$13x - 14y + 47 = 0$
- C
$13x + 14y + 47 = 0$
- D
$13x + 14y - 47 = 0$
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