The velocity of light in air is 3 times 10^8 | vedclass

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(C) According to Brewster's Law,the polarising angle $i_p$ is related to the refractive index $\mu$ by the formula: $i_p = 	an^{-1}(\mu)$.Refractive

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$53.74$

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(C) According to Brewster's Law,the polarising angle $i_p$ is related to the refractive index $\mu$ by the formula: $i_p = 	an^{-1}(\mu)$.Refractive index $\mu$ is the ratio of the velocity of light in air $(c)$ to the velocity of light in the medium $(v)$: $\mu = \frac{c}{v}$.Given $c = 3 	imes 10^8 \, ms^{-1}$ and $v = 2.2 	imes 10^8 \, ms^{-1}$.Calculating $\mu$: $\mu = \frac{3 	imes 10^8}{2.2 	imes 10^8} = \frac{3}{2.2} \approx 1.3636$.Now,$i_p = 	an^{-1}(1.3636) \approx 53.74^o$.

The velocity of light in air is $3 \times 10^8 \, ms^{-1}$ and that in water is $2.2 \times 10^8 \, ms^{-1}$. The polarising angle of incidence is.......$^o$

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