The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index $n$) is:

$A$ beam of light both reflects and refracts at the surface between air and glass. The refractive index of the glass is $1.4$. If the refracted and the reflected rays are perpendicular to each other,then the angle of incidence in the air is

Given below are two statements:
Statement $I$: If the Brewster's angle for the light propagating from air to glass is $\theta_B$,then Brewster's angle for the light propagating from glass to air is $\frac{\pi}{2} - \theta_B$.
Statement $II$: The Brewster's angle for the light propagating from glass to air is $\tan^{-1}(\mu_g)$ where $\mu_g$ is the refractive index of glass.
In the light of the above statements,choose the correct answer from the options given below:

At what angle of incidence,the light reflected from a glass slab will become completely polarised,if the angle of refraction at that incident angle is $33.6^{\circ}$ (in $^{\circ}$)?

$A$ beam of light $AO$ is incident on a glass slab $(\mu = 1.54)$ in a direction as shown in the figure. The reflected ray $OB$ is passed through a Nicol prism. On viewing through the rotating Nicol prism,we find that $(\tan 57^{\circ} = 1.54)$.

$A$ ray of light is incident on the surface of a glass plate at Brewster's angle $\phi$. If $\mu$ is the refractive index of glass with respect to air,then the angle between the reflected and the refracted ray is: