The variation of displacement with time of a | vedclass

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(D) The given displacement equation for $SHM$ is $y = 2 \sin \left(\frac{\pi t}{2} + \phiight) 	ext{ cm}$.Comparing this with the standard $SHM$ eq

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$\frac{\pi^2}{2} 	ext{ cm/s}^2$

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(D) The given displacement equation for $SHM$ is $y = 2 \sin \left(\frac{\pi t}{2} + \phiight) 	ext{ cm}$.Comparing this with the standard $SHM$ equation $y = A \sin(\omega t + \phi)$,we get the amplitude $A = 2 	ext{ cm}$ and angular frequency $\omega = \frac{\pi}{2} 	ext{ rad/s}$.The formula for maximum acceleration in $SHM$ is $a_{\max} = \omega^2 A$.Substituting the values,we get $a_{\max} = \left(\frac{\pi}{2}ight)^2 	imes 2$.$a_{\max} = \frac{\pi^2}{4} 	imes 2 = \frac{\pi^2}{2} 	ext{ cm/s}^2$.

The variation of displacement with time of a simple harmonic motion $(SHM)$ for a particle of mass $m$ is represented by $y = 2 \sin \left(\frac{\pi t}{2} + \phi\right) \text{ cm}$. The maximum acceleration of the particle is

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