Assertion : In SHM,acceleration is always dir | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $SHM$ is defined as a to-and-fro motion about a mean position. The restoring force,and consequently the acceleration,is always directed towards th

Vedclass · Accepted Answer

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

Vedclass · Answer

(A) $SHM$ is defined as a to-and-fro motion about a mean position. The restoring force,and consequently the acceleration,is always directed towards the mean position to bring the body back. The acceleration in $SHM$ is given by $a = -\omega^2 x$,where $x$ is the displacement from the mean position. Since the negative sign indicates that the acceleration is always opposite to the direction of displacement,it is always directed towards the mean position. The reason provided correctly explains that the body must stop at the extreme position and return to the mean position due to this acceleration. Therefore,both statements are correct and the reason explains the assertion.

$Assertion :$ In $SHM$,acceleration is always directed towards the mean position.
$Reason :$ In $SHM$,the body has to stop momentarily at the extreme position and move back to the mean position.

Similar Questions

The amplitude of a particle executing $SHM$ is $2 \, cm$ and the force acting at the extreme position on the particle is $4 \, N$. What is the force at the midway point between the mean position and the extreme point (in $, N$)?

What is the phase difference between the displacement and acceleration of a particle executing $SHM$?

In simple harmonic motion,the ratio of acceleration of the particle to its displacement at any time is a measure of

$A$ point mass oscillates along the $X$-axis according to the law $x=x_0 \cos \left(\omega t-\frac{\pi}{4}\right)$. If the acceleration of the particle is written as $a=A \cos (\omega t-\delta)$,then

The displacement of a particle performing $S.H.M.$ is given by $x=5 \sin (3 t+3)$,where $x$ is in $cm$ and $t$ is in $s$. The maximum acceleration of the particle will be (in $cm \ s^{-2}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Assertion :$ In $SHM$,acceleration is always directed towards the mean position.$Reason :$ In $SHM$,the body has to stop momentarily at the extreme position and move back to the mean position.