The variance of the data 2, 4, 6, 8, 10 is | vedclass

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(c) Here, $\bar x = \frac{{2 + 4 + 6 + 8 + 10}}{5} = 6$

Hence, variance = $\frac{1}{n}\Sigma {({x_i} - \overline x )^2}$

$ = \frac{1}{5}\{ {(2 -

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$8$

Vedclass · Answer

(c) Here, $\bar x = \frac{{2 + 4 + 6 + 8 + 10}}{5} = 6$

Hence, variance = $\frac{1}{n}\Sigma {({x_i} - \overline x )^2}$

$ = \frac{1}{5}\{ {(2 - 6)^2} + {(4 - 6)^2} + {(6 - 6)^2} + {(8 - 6)^2} + {(10 - 6)^2}\} $

$ = \frac{1}{5}\left\{ {(16 + 4 + 0 + 4 + 16} \right\}$$ = \frac{1}{5}\left\{ {40} \right\}$ $ = 8$.

class	$0-10$	$10-20$	$20-30$	$30-40$
Freq	$1$	$3$	$4$	$2$

$X$	$c$	$2c$	$3c$	$4c$	$5c$	$6c$
$f$	$2$	$1$	$1$	$1$	$1$	$1$

The variance of the data $2, 4, 6, 8, 10$ is

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