The variance of $10$ observations is $16$. If each observation is doubled, then standard deviation of new data will be -
The variance of $10$ observations is $16$. If each observation is doubled, then standard deviation of new data will be -
- A
$16$
- B
$32$
- C
$8$
- D
$4$
Similar Questions
Find the standard deviation for the following data:
${x_i}$
$3$
$8$
$13$
$18$
$25$
${f_i}$
$7$
$10$
$15$
$10$
$6$
Find the standard deviation for the following data:
| ${x_i}$ | $3$ | $8$ | $13$ | $18$ | $25$ |
| ${f_i}$ | $7$ | $10$ | $15$ | $10$ | $6$ |
If the mean of the frequency distribution
Class:
$0-10$
$10-20$
$20-30$
$30-40$
$40-50$
Frequency
$2$
$3$
$x$
$5$
$4$
is $28$ , then its variance is $........$.
If the mean of the frequency distribution
| Class: | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ |
| Frequency | $2$ | $3$ | $x$ | $5$ | $4$ |
is $28$ , then its variance is $........$.
- [JEE MAIN 2023]
If both the means and the standard deviation of $50$ observations $x_1, x_2, ………, x_{50}$ are equal to $16$ , then the mean of $(x_1 - 4)^2, (x_2 - 4)^2, …., (x_{50} - 4)^2$ is
If both the means and the standard deviation of $50$ observations $x_1, x_2, ………, x_{50}$ are equal to $16$ , then the mean of $(x_1 - 4)^2, (x_2 - 4)^2, …., (x_{50} - 4)^2$ is
- [JEE MAIN 2019]
For a statistical data $x _1, x _2, \ldots, x _{10}$ of $10$ values, a student obtained the mean as $5.5$ and $\sum_{i=1}^{10} x _{ i }^2=371$. He later found that he had noted two values in the data incorrectly as $4$ and $5$ , instead of the correct values $6$ and $8$ , respectively. The variance of the corrected data is
- [JEE MAIN 2025]
Calculate the mean, variance and standard deviation for the following distribution:
Class
$30-40$
$40-50$
$50-60$
$60-70$
$70-80$
$80-90$
$90-100$
$f_i$
$3$
$7$
$12$
$15$
$8$
$3$
$2$
Calculate the mean, variance and standard deviation for the following distribution:
| Class | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ | $80-90$ | $90-100$ |
| $f_i$ | $3$ | $7$ | $12$ | $15$ | $8$ | $3$ | $2$ |