The magnitude of the sum of two vectors vec{A | vedclass

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(A) The resultant vector $\vec{R}$ of two vectors $\vec{A}$ and $\vec{B}$ is given by the vector addition rule: $\vec{R} = \vec{A} + \vec{B}$.The magn

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$\sqrt{A^2 + B^2 + 2AB \cos 	heta}$

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(A) The resultant vector $\vec{R}$ of two vectors $\vec{A}$ and $\vec{B}$ is given by the vector addition rule: $\vec{R} = \vec{A} + \vec{B}$.The magnitude of the resultant vector is calculated using the parallelogram law of vector addition.The formula for the magnitude $R$ is given by:$R = |\vec{A} + \vec{B}| = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$,where $A$ and $B$ are the magnitudes of vectors $\vec{A}$ and $\vec{B}$ respectively,and $	heta$ is the angle between them.

The magnitude of the sum of two vectors $\vec{A}$ and $\vec{B}$ with $\theta$ as the angle between them is:

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