The value of the horizontal component of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The horizontal component of the earth's magnetic field is given by $B_H = B \cos \phi$,where $B$ is the total intensity and $\phi$ is the angle of

Vedclass · Accepted Answer

$2.08 	imes 10^{-5} \, Wb/m^2$

Vedclass · Answer

(A) The horizontal component of the earth's magnetic field is given by $B_H = B \cos \phi$,where $B$ is the total intensity and $\phi$ is the angle of dip.Given: $B_H = 1.8 	imes 10^{-5} \, Wb/m^2$ and $\phi = 30^{\circ}$.We need to find the total intensity $B = \frac{B_H}{\cos \phi}$.Substituting the values: $B = \frac{1.8 	imes 10^{-5}}{\cos 30^{\circ}}$.Since $\cos 30^{\circ} = \frac{\sqrt{3}}{2} \approx 0.866$,we have $B = \frac{1.8 	imes 10^{-5}}{0.866} \approx 2.08 	imes 10^{-5} \, Wb/m^2$.

The value of the horizontal component of the earth's magnetic field and the angle of dip are $1.8 \times 10^{-5} \, Wb/m^2$ and $30^{\circ}$ respectively at a certain place. The total intensity of the earth's magnetic field at that place will be:

Similar Questions

The dip angle in a vertical plane at an angle of $\cos^{-1} \left( \frac{1}{\sqrt{2}} \right)$ from the magnetic meridian is $60^\circ$. Find the actual dip angle at that place.

At a certain place,the horizontal component ${B_0}$ and the vertical component ${V_0}$ of the Earth's magnetic field are equal in magnitude. The total intensity at the place will be

The correct relation is:
$B_H$ = Horizontal component of earth's magnetic field; $B_V$ = Vertical component of earth's magnetic field and $B$ = Total intensity of earth's magnetic field.

If the angles of dip at two places are $30^{\circ}$ and $45^{\circ}$ respectively,then the ratio of horizontal components of earth's magnetic field at the two places will be

The horizontal component of the Earth's magnetic field is $0.22 \ G$ and the total magnetic field is $0.4 \ G$. The angle of dip is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module