In the magnetic meridian of a certain place, the horizontal component of the earth’s magnetic field is $0.26\;G$ and the dip angle is $60^o$. What is the magnetic field of the earth at this location?
$0.52\; G$
$0.26\; G$
$0.13\; G$
$0.86\; G$
A dip needle vibrates in the vertical plane perpendicular to the magnetic meridian. The time period of vibration is found to be $2$ seconds. The same needle is then allowed to vibrate in the horizontal plane and the time period is again found to be $2$ seconds. Then the angle of dip is.....$^o$
The earth's magnetic field lines resemble that of a dipole at the centre of the earth. If the magnetic moment of this dipole is close to $8 \times 10^{22}\, Am^2$, the value of earth 's magnetic field near the equator is close to....$Gauss$ (radius of the earth $= 6.4 \times 10^6\, m$)
A magnet is placed horizontally on ground with its north pole towards the geographic north pole of the earth. The neutral point is obtained
The earth's magnetic field at a certain place has a horizontal component $0.3$ $Gauss$ and the total strength $0.5$ $Gauss$. The angle of dip is
The values of the apparent angles of dip in two planes at right angles to each other are $45^{\circ}$ and $30^{\circ}$ respectively. The true value of angle of dip at the place is ............