The value of the gas constant $(R)$ calculated from the perfect gas equation is $8.32 \ J/mol \cdot K$,whereas its value calculated from the knowledge of $C_P$ and $C_V$ of the gas is $1.98 \ cal/mol \cdot K$. From this data,the value of $J$ is ......... $J/cal$.

  • A
    $4.16$
  • B
    $4.18$
  • C
    $4.20$
  • D
    $4.22$

Explore More

Similar Questions

According to the law of equipartition of energy, the molar specific heat of a diatomic gas at constant volume, where the molecule has one additional vibrational mode, is:

Obtain the value of $\frac{C_{P}}{C_{V}}$ for a polyatomic gas.

If the difference between the specific heats of a gas is $4150 \, J/kg \cdot K$ and the ratio of specific heats is $1.4$,then the specific heat at constant volume is ...... $J/kg \cdot K$.

Molar specific heat at constant pressure $C_p$ is related to internal energy $U$ and absolute temperature $T$ as $C_p$ is equal to

At constant volume,for different diatomic gases the molar specific heat is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo