$\cos (\tan^{-1} x)$ का मान . . . . . . के बराबर है : (जहाँ $|x| < 1$)

  • A
    $\frac{1}{\sqrt{1+x^2}}$
  • B
    $\frac{1}{\sqrt{1-x^2}}$
  • C
    $\frac{x}{\sqrt{1-x^2}}$
  • D
    $\frac{x}{\sqrt{1+x^2}}$

Explore More

Similar Questions

समीकरण $\sin ^{-1} x+\sin ^{-1} 2 x=\frac{\pi}{3}$ का हल है

$\cos ^{-1}\left(\tan \left(\frac{7 \pi}{4}\right)\right)$ का मान है

$\tan \left[ \frac{1}{2} \cos^{-1} \left( \frac{\sqrt{5}}{3} \right) \right] = $

यदि प्रतिलोम त्रिकोणमितीय फलन मुख्य मान लेते हैं,तो $\cos ^{-1}\left(\frac{3}{10} \cos \left(\tan ^{-1}\left(\frac{4}{3}\right)\right)+\frac{2}{5} \sin \left(\tan ^{-1}\left(\frac{4}{3}\right)\right)\right)$ का मान ज्ञात कीजिए।

$\tan \left( 2{{\cos }^{ - 1}}\frac{3}{5} \right) = $

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo