2({sin ^6}theta + {cos ^6}theta ) - 3({ | vedclass

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Question

${({\sin ^2}	heta  + {\cos ^2}	heta )^3} = {(1)^3}$

$ \Rightarrow \,\,{\sin ^6}	heta  + {\cos ^6}	heta  + 3\,{\sin ^2}	heta \,{

Vedclass · Accepted Answer

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Vedclass · Answer

${({\sin ^2}	heta  + {\cos ^2}	heta )^3} = {(1)^3}$

$ \Rightarrow \,\,{\sin ^6}	heta  + {\cos ^6}	heta  + 3\,{\sin ^2}	heta \,{\cos ^2}	heta  = 1$

तथा ${\sin ^4}	heta  + {\cos ^4}	heta  + 2\,{\sin ^2}	heta \,{\cos ^2}	heta  = 1$

$	herefore$ $2\,\,({\sin ^6}	heta  + {\cos ^6}	heta ) - 3\,({\sin ^4}	heta  + {\cos ^4}	heta ) + 1 = 0$.

$2({\sin ^6}\theta + {\cos ^6}\theta ) - 3({\sin ^4}\theta + {\cos ^4}\theta ) + 1$ का मान है

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