The units of length,velocity,and force are do | vedclass

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(C) Let the original units be $L$,$v$,and $F$. The new units are $L' = 2L$,$v' = 2v$,and $F' = 2F$.We know that velocity $v = L/T$,so the unit of time

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Unit of momentum is doubled

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(C) Let the original units be $L$,$v$,and $F$. The new units are $L' = 2L$,$v' = 2v$,and $F' = 2F$.We know that velocity $v = L/T$,so the unit of time $T = L/v$. The new unit of time $T' = L'/v' = (2L)/(2v) = L/v = T$. Thus,the unit of time remains unchanged.We know that force $F = ma = m(v/T)$,so the unit of mass $m = FT/v$. The new unit of mass $m' = F'T'/v' = (2F 	imes T)/(2v) = FT/v = m$. Thus,the unit of mass remains unchanged.We know that momentum $p = mv$. The new unit of momentum $p' = m'v' = m 	imes (2v) = 2mv = 2p$. Thus,the unit of momentum is doubled.We know that energy $E = F 	imes L$. The new unit of energy $E' = F' 	imes L' = (2F) 	imes (2L) = 4FL = 4E$. Thus,the unit of energy becomes four times the original value.Therefore,the correct statement is that the unit of momentum is doubled.

List-$I$	List-$II$
$A$. Boltzmann constant	$I$. $[M^{-1}L^3T^{-2}]$
$B$. Stefan's constant	$II$. $[ML^2T^{-1}]$
$C$. Planck's constant	$III$. $[ML^2T^{-2}K^{-1}]$
$D$. Gravitational constant	$IV$. $[ML^0T^{-3}K^{-4}]$

The units of length,velocity,and force are doubled. Which of the following is the correct change in the other units?

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