The difference in the lengths of a mean solar day and a sidereal day is about........$min$.

  • A
    $1$
  • B
    $4$
  • C
    $15$
  • D
    $56$

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Similar Questions

Choose the correct match:
List-$I$ List-$II$
$(i)$ Curie $(A)$ $MLT^{-2}$
$(ii)$ Light year $(B)$ $M$
$(iii)$ Dielectric strength $(C)$ Dimensionless
$(iv)$ Atomic weight $(D)$ $T$
$(v)$ Decibel $(E)$ $ML^2T^{-2}$
$(F)$ $MT^{-3}$
$(G)$ $T^{-1}$
$(H)$ $L$
$(I)$ $MLT^{-3}I^{-1}$
$(J)$ $LT^{-1}$

The quantities which have the same dimensions as those of solid angle are:

$Pascal-Second$ has the dimension of:

The unit $J \cdot s^2$ corresponds to which physical quantity?

To determine the Young's modulus of a wire,the formula is $Y = \frac{FL}{A\Delta L}$,where $L$ is the length,$A$ is the area of cross-section of the wire,and $\Delta L$ is the change in length of the wire when stretched with a force $F$. The conversion factor to change the unit of Young's modulus from $CGS$ to $MKS$ system is $x \times 10^{-1} \ N/m^2$. Find the value of $x$.

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