The two vectors have magnitudes 3 and 5. If t | vedclass

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(A) The dot product of two vectors $\vec{A}$ and $\vec{B}$ is given by the formula: $\vec{A} \cdot \vec{B} = AB \cos 	heta$.Given magnitudes are $A =

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$7.5$

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(A) The dot product of two vectors $\vec{A}$ and $\vec{B}$ is given by the formula: $\vec{A} \cdot \vec{B} = AB \cos 	heta$.Given magnitudes are $A = 3$ and $B = 5$.The angle between them is $	heta = 60^o$.Substituting the values into the formula:$\vec{A} \cdot \vec{B} = 3 	imes 5 	imes \cos(60^o)$.Since $\cos(60^o) = 0.5$,we get:$\vec{A} \cdot \vec{B} = 15 	imes 0.5 = 7.5$.

The two vectors have magnitudes $3$ and $5$. If the angle between them is $60^o$,then the dot product of the two vectors will be:

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