The truth values of p rightarrow r is F and p | vedclass

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(A) Given that the truth value of $p \rightarrow r$ is $F$,we must have $p \equiv T$ and $r \equiv F$.Given that the truth value of $p \leftrightarrow

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$T, F$

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(A) Given that the truth value of $p \rightarrow r$ is $F$,we must have $p \equiv T$ and $r \equiv F$.Given that the truth value of $p \leftrightarrow q$ is $F$,and we know $p \equiv T$,it follows that $q \equiv F$.Now,evaluate the first expression: $(\sim p \vee q) \rightarrow (p \vee \sim q)$$= (\sim T \vee F) \rightarrow (T \vee \sim F)$$= (F \vee F) \rightarrow (T \vee T)$$= F \rightarrow T \equiv T$.Now,evaluate the second expression: $(p \wedge \sim q) \rightarrow (\sim p \wedge q)$$= (T \wedge \sim F) \rightarrow (\sim T \wedge F)$$= (T \wedge T) \rightarrow (F \wedge F)$$= T \rightarrow F \equiv F$.Thus,the truth values are $T, F$.

The truth values of $p \rightarrow r$ is $F$ and $p \leftrightarrow q$ is $F$. Then the truth values of $(\sim p \vee q) \rightarrow (p \vee \sim q)$ and $(p \wedge \sim q) \rightarrow (\sim p \wedge q)$ are respectively:

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