The statement pattern (p wedge q) vee (sim p | vedclass

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(C) We simplify the given expression using the laws of logic:$(p \wedge q) \vee (\sim p \wedge q) \vee (r \wedge \sim q)$Using the distributive law on

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$q \vee r$

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(C) We simplify the given expression using the laws of logic:$(p \wedge q) \vee (\sim p \wedge q) \vee (r \wedge \sim q)$Using the distributive law on the first two terms:$\equiv \{(p \vee \sim p) \wedge q\} \vee (r \wedge \sim q)$Since $(p \vee \sim p) \equiv t$ (tautology):$\equiv (t \wedge q) \vee (r \wedge \sim q)$$\equiv q \vee (r \wedge \sim q)$Applying the distributive law $A \vee (B \wedge C) \equiv (A \vee B) \wedge (A \vee C)$:$\equiv (q \vee r) \wedge (q \vee \sim q)$Since $(q \vee \sim q) \equiv t$:$\equiv (q \vee r) \wedge t$$\equiv q \vee r$

The statement pattern $(p \wedge q) \vee (\sim p \wedge q) \vee (r \wedge \sim q)$ is logically equivalent to:

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