The triangle formed by the lines x + y - 4 = | vedclass

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Question

(a) The vertices of triangle are the intersection points of these given lines. The vertices of

$\Delta $ are $A(0,\,4),$ $B(1,2),$$C(4,0)$

Now,

Vedclass · Accepted Answer

Isosceles

Vedclass · Answer

(a) The vertices of triangle are the intersection points of these given lines. The vertices of

$\Delta $ are $A(0,\,4),$ $B(1,2),$$C(4,0)$

Now, $AB = \sqrt {{{(0 - 1)}^2} + {{(4 - 1)}^2}} = \sqrt {10} $

$BC = \sqrt {{{(1 - 4)}^2} + {{(0 - 1)}^2}} = \sqrt {10} $

$AC = \sqrt {{{(0 - 4)}^2} + {{(0 - 4)}^{}}} = 4\sqrt 2 $

$\because AB = BC$; $\bigtriangleup$ is isosceles.

The triangle formed by the lines $x + y - 4 = 0,\,$ $3x + y = 4,$ $x + 3y = 4$ is

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