The trajectory of projectile, projected from the ground is given by $y=x-\frac{x^2}{20}$. Where $x$ and $y$ are measured in meter. The maximum height attained by the projectile will be $...........\,m$
The trajectory of projectile, projected from the ground is given by $y=x-\frac{x^2}{20}$. Where $x$ and $y$ are measured in meter. The maximum height attained by the projectile will be $...........\,m$
- [JEE MAIN 2023]
- A
$5$
- B
$10 \sqrt{2}$
- C
$200$
- D
$10$
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- [AIIMS 2009]
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