The total number of unpaired electrons present in the complex $K_3[Cr(C_2O_4)_3]$ is ..........

  • A
    $3$
  • B
    $9$
  • C
    $7$
  • D
    $2$

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Similar Questions

Calculate the total number of stereoisomers for the octahedral complex $[Fe(F)(Cl)(Br)(I)(NH_3)(H_2O)]^-$.

Match List-$I$ with List-$II$.
List-$I$ (Complex) List-$II$ (Type of isomerism)
$A$. $[Co(NH_3)_5(NO_2)]Cl_2$ $I$. Solvate isomerism
$B$. $[Co(NH_3)_5(SO_4)]Br$ $II$. Linkage isomerism
$C$. $[Co(NH_3)_6][Cr(CN)_6]$ $III$. Ionization isomerism
$D$. $[Co(H_2O)_6]Cl_3$ $IV$. Coordination isomerism

Choose the correct answer from the options given below:

For an octahedral complex $MX_{4}Y_{2}$ ($M=$ a transition metal,$X$ and $Y$ are monodentate achiral ligands),the correct statement among the following is

The total number of isomers for the square planar complex $K_2[PdClBr_2(SCN)]$ is/are:

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Among the following complexes,the total number of diamagnetic species is. . . . $[Mn(NH_3)_6]^{3+}, [MnCl_6]^{3-}, [FeF_6]^{3-}, [CoF_6]^{3-}, [Fe(NH_3)_6]^{3+}$ and $[Co(en)_3]^{3+}$
[Given,atomic number: $Mn=25, Fe=26, Co=27$; $en=H_2NCH_2CH_2NH_2$ ]

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