Among the following complexes,the total numbe | vedclass

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(A) $Mn^{3+} (3d^4)$: In both strong and weak fields,it has unpaired electrons. Hence,$[Mn(NH_3)_6]^{3+}$ and $[MnCl_6]^{3-}$ are paramagnetic.$Fe^{3+

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(A) $Mn^{3+} (3d^4)$: In both strong and weak fields,it has unpaired electrons. Hence,$[Mn(NH_3)_6]^{3+}$ and $[MnCl_6]^{3-}$ are paramagnetic.$Fe^{3+} (3d^5)$: In both strong and weak fields,it has unpaired electrons. Hence,$[FeF_6]^{3-}$ and $[Fe(NH_3)_6]^{3+}$ are paramagnetic.$Co^{3+} (3d^6)$: $1$. $[CoF_6]^{3-}$: $F^-$ is a weak field ligand,so it forms a high-spin complex with $t_{2g}^4 e_g^2$ configuration,which is paramagnetic.$2$. $[Co(en)_3]^{3+}$: $en$ is a strong field ligand,so it forms a low-spin complex with $t_{2g}^6 e_g^0$ configuration,which is diamagnetic.Thus,only $[Co(en)_3]^{3+}$ is diamagnetic. The total number of diamagnetic species is $1$.

Among the following complexes,the total number of diamagnetic species is. . . . $[Mn(NH_3)_6]^{3+}, [MnCl_6]^{3-}, [FeF_6]^{3-}, [CoF_6]^{3-}, [Fe(NH_3)_6]^{3+}$ and $[Co(en)_3]^{3+}$
[Given,atomic number: $Mn=25, Fe=26, Co=27$; $en=H_2NCH_2CH_2NH_2$ ]

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Among the following complexes,the total number of diamagnetic species is. . . . $[Mn(NH_3)_6]^{3+}, [MnCl_6]^{3-}, [FeF_6]^{3-}, [CoF_6]^{3-}, [Fe(NH_3)_6]^{3+}$ and $[Co(en)_3]^{3+}$[Given,atomic number: $Mn=25, Fe=26, Co=27$; $en=H_2NCH_2CH_2NH_2$ ]