For an octahedral complex MX_{4}Y_{2} (M= a t | vedclass

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(B) The complex $MX_{4}Y_{2}$ exhibits two geometrical isomers: $cis$ and $trans$.In the $trans$ isomer,the two $Y$ ligands are at $180^{\circ}$ to ea

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$MX_{4}Y_{2}$ has $2$ geometrical isomers both of which are achiral

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(B) The complex $MX_{4}Y_{2}$ exhibits two geometrical isomers: $cis$ and $trans$.In the $trans$ isomer,the two $Y$ ligands are at $180^{\circ}$ to each other. This isomer possesses a center of symmetry and multiple planes of symmetry,making it achiral.In the $cis$ isomer,the two $Y$ ligands are at $90^{\circ}$ to each other. This isomer possesses planes of symmetry,making it also achiral.Thus,both geometrical isomers are achiral.

For an octahedral complex $MX_{4}Y_{2}$ ($M=$ a transition metal,$X$ and $Y$ are monodentate achiral ligands),the correct statement among the following is

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