The term independent of x in the expansion of | vedclass

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Question

(d) ${T_{r + 1}} = \,{}^6{C_r}{(2x)^{6 - r}}{\left( { - \frac{3}{x}} \right)^r}$

= ${}^6{C_r}{(2)^{6 - r}}{( - 3)^r}{(x)^{6 - 2r}}$

Vedclass · Accepted Answer

$-4320$

Vedclass · Answer

(d) ${T_{r + 1}} = \,{}^6{C_r}{(2x)^{6 - r}}{\left( { - \frac{3}{x}} ight)^r}$

= ${}^6{C_r}{(2)^{6 - r}}{( - 3)^r}{(x)^{6 - 2r}}$  

For term independent of $x$, $6 -2r = 0$ i.e. $r = 3$ 

$	herefore  {T_4} = {\,^6}{C_3}\,{2^{6 - 3}}{( - 3)^3}$ $= -4320$.

The term independent of $x$ in the expansion of ${\left( {2x - \frac{3}{x}} \right)^6}$ is

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