The temperature of $100 \,g$ of water is to be raised from $24^{\circ} C$ to $90^{\circ} C$ by adding steam at $100^{\circ} C$ to it. The mass of the steam required in this process is (latent heat of steam is $540 \,cal \,g^{-1}$). (in $\,g$)

  • A
    $2$
  • B
    $4$
  • C
    $10$
  • D
    $12$

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Similar Questions

$A$ calorimeter contains $0.2 \ kg$ of water at $30^{\circ}C$. When $0.1 \ kg$ of water at $60^{\circ}C$ is added to it,the final temperature of the mixture becomes $35^{\circ}C$. What is the heat capacity of the calorimeter in $J/K$?

The temperatures of equal masses of three different liquids $x$,$y$,and $z$ are $10^{\circ}C$,$20^{\circ}C$,and $30^{\circ}C$ respectively. The temperature of the mixture when $x$ is mixed with $y$ is $16^{\circ}C$,and the temperature when $y$ is mixed with $z$ is $26^{\circ}C$. The temperature of the mixture when $x$ and $z$ are mixed will be ...... $^{\circ}C$.

When $100\,g$ of a liquid $A$ at $100\,^oC$ is added to $50\,g$ of a liquid $B$ at temperature $75\,^oC$,the temperature of the mixture becomes $90\,^oC$. The temperature of the mixture,if $100\,g$ of liquid $A$ at $100\,^oC$ is added to $50\,g$ of liquid $B$ at $50\,^oC$,will be ........$^oC$

Three containers $C_{1}, C_{2}$ and $C_{3}$ have water at different temperatures. The table below shows the final temperature $T$ when different amounts of water (given in litres) are taken from each container and mixed (assume no loss of heat during the process).
$C_{1}$$C_{2}$$C_{3}$$T$
$1 \ l$$2 \ l$$-$$60^{\circ} C$
$-$$1 \ l$$2 \ l$$30^{\circ} C$
$2 \ l$$-$$1 \ l$$60^{\circ} C$
$1 \ l$$1 \ l$$1 \ l$$\theta$

The value of $\theta$ (in $^{\circ} C$ to the nearest integer) is

Steam at $100\,^{\circ}C$ is passed into $20\,g$ of water at $10\,^{\circ}C$. When water acquires a temperature of $80\,^{\circ}C$,the mass of water present will be ........ $g$. [Take specific heat of water $= 1\,cal\,g^{-1}\,^{\circ}C^{-1}$ and latent heat of steam $= 540\,cal\,g^{-1}$]

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