The temperature-entropy (T-S) diagram of a re | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The area under the $T-S$ curve represents the heat exchanged in a process.For the given cycle, the heat absorbed $(Q_{in})$ is the area under the

Vedclass · Accepted Answer

$0.33$

Vedclass · Answer

(A) The area under the $T-S$ curve represents the heat exchanged in a process.For the given cycle, the heat absorbed $(Q_{in})$ is the area under the top slanted line from $S_0$ to $2S_0$.The area is a rectangle plus a triangle: $Q_{in} = (T_0 	imes S_0) + \frac{1}{2} 	imes (2T_0 - T_0) 	imes (2S_0 - S_0) = T_0 S_0 + \frac{1}{2} T_0 S_0 = 1.5 T_0 S_0$.The heat rejected $(Q_{out})$ is the area under the bottom horizontal line from $2S_0$ to $S_0$ at temperature $T_0$: $Q_{out} = T_0 	imes (2S_0 - S_0) = T_0 S_0$.The efficiency $\eta$ is given by $\eta = 1 - \frac{Q_{out}}{Q_{in}}$.Substituting the values: $\eta = 1 - \frac{T_0 S_0}{1.5 T_0 S_0} = 1 - \frac{1}{1.5} = 1 - \frac{2}{3} = \frac{1}{3} \approx 0.33$.

The temperature-entropy $(T-S)$ diagram of a reversible engine cycle is given in the figure. Its efficiency is

Similar Questions

The value of efficiency $\eta$ for a heat engine may lie between

The temperature of the sink of a Carnot engine is $250 \ K$. In order to increase the efficiency of the Carnot engine from $25 \%$ to $50 \%$,the temperature of the sink should be increased by

The efficiency of a Carnot engine is $100\%$ if

In practice,all heat engines have an efficiency less than that of a Carnot engine because

Consider a reversible engine of efficiency $\frac{1}{6}$. When the temperature of the sink is reduced by $62^{\circ} C$, its efficiency gets doubled. The temperature of the source and sink respectively are

Vedclass Test Series

Exam Paper Generator

Online Exam Module